I think it makes sense to look at this problem generally.
A (B/C) is also the same thing as ((AB)/C). For a problem like ((AB)/C) plus or minus ((DE)/F), we can’t really do anything with this. We want the same denominator (we want C and F to be the same thing). We can do this by realizing that ((AB)/C) is the same thing as ((2AB)/(2C)).
((FAB)/(FC)) plus or minus ((CDE)/(CF)) makes it so that the denominator is the same on both sides (CF or FC), and then you can add or subtract FAB with CDE. Afterwards, we can divide the top result by your denominator.
To use your numbers:
5 (3/4) – 6 (3/4)
15/4 – 18-4
-3/4.
Let’s say we instead had
5(3/4) – 6(3/5)
(15/4) – (18/5)
((5×15)/(5×4)) – ((4×15)/4×5))
(75/20) – (72/20)
3/20.
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