I was wondering about how sound is calculated to get energy, I heard that you can get Watts from the Intensity (W/m\^2) \* by Area (m\^2), so just to avoid misuse of the term, is Intensity equality distributed across said area or can it be used regardless with how it can travel from the source at the center?
Here are some values for comprehension:
* Area = 8.27e+14 m\^2
* Radius = 8113840 meters
* Intensity = 0.032 W/m\^s
* Decibels = 105 (Sound needed to shatter glass) all the way to the edge.
In: Physics
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