In a game where a guy has a 20% win probabiliy in each round. What’s the probabiliy for him to win at least one time after six attempts? It can’t be 120%. I know there is a way to calculate this but idk.
In: Mathematics
Typically you multiply probabilities.
So if you had a 20% chance to win, and you wanted to know the probability of winning twice in a row, you would do 20% x 20% = 4%. For more wins in a row you would simply add more multiplication.
On the other hand, you have an 80% chance to lose. If you wanted to know the probability of losing twice in a row you would do 80% x 80% = 64%.
You’ll notice that that only adds to 68%, meaning you have a 32% chance of winning *only *once.
So the short answer is that the easiest way to find winning *at least* once you find the probabilities of winning zero times and subtract that percentage from 100%.
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