If you just mean the sum of heads in the first 10 vs the sum of heads in the second 10, then you’d calculate the likelihood for each number (0 heads, 1 head, 2 heads, … 10 heads), then square them for the odds of getting the same result twice in a row. Add those squared numbers and you’d get the overall odds, which comes out to 17.6197052%
For instance…
0 heads. The odds of that happening are 1 in 1024. So in those 1 out of 1024 times, you have 1 out of 1024 odds of it happening again, so roughly 1 in a million.
5 heads — the odds of getting 5 heads is 252 in 1024 (~24.6%). The odds of getting 5 heads AGAIN is 252 out of 1024, so the odds of that happening are 252^2 / 1024^2, or around 6%.
Just to verify, I wrote a quick and dirty program to actually do this 100 million times… It happened to get 17.617303%
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