[eli5] Why is imaginary number root -1? Why not root -n, since no number times each other would result in negative number?

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[eli5] Why is imaginary number root -1? Why not root -n, since no number times each other would result in negative number?

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Anonymous 0 Comments

That’s because people chose i = sqrt(-1) as a basis for imaginary numbers, like 1 = sqrt(1) is the basis for real ones.

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