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Disclaimer: I don’t think that this will elif, but it may still help.
*x = x^1 = x^0+1 = x^0 * x^1 = x^0 * x*.
So we have that
*x = x^0 * x*.
Divide both sides by *x* to get that
*1 = x^0 .*
I should note that we assume that *x* is not zero, but I don’t think that’s important for this explanation
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