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You basically follow the pattern:
>x^(n+1) = x * x^n
or the other way around
>x^(n) = x^(x+1)/ x
Now if you plug in the examples
>x^1 = x * x^0
as x^1 = x therefore x^0 must be 1. Or even more intuitively for the other example:
>x^0 = x^1/x
well x^1 = x and x/x = 1 so x^0 is equal to 1
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