For particles traveling close to (or at) the speed of light, momentum isn’t directly related to (rest) mass. The usual equation p = mv does not apply at high speeds, and you need the full relativistic equation E^2 = (mc^(2))^2 + (pc)^(2) (where E is energy, m is rest mass, p is momentum, and c is the speed of light). At low speeds, and for non-zero masses, this reduces to the usual p = mv as a very very close approximation, but like most formulas in classical physics it’s just an approximation to the true relativistic formula.
Put another way, light *does* have mass(-energy). It just doesn’t have *rest* mass. But since a photon is never *at* rest, it isn’t massless in the sense that you wouldn’t feel it if it bumped into you.
Because of the famous e=mc^2
Mass can be converted into a lot of energy, and energy can be converted into a little bit of mass.
Now the actually physics is more complicated, but to put simply if e=mc^2 (where c is the speed of light) then m=e/c^2
So you can substitute back and force between m and e, it’s not entirely that simple, the math is a bit more complex, but that is the premise.
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