How do black holes “consume” light?
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Imagine the trajectory of a thrown ball. Imagine a planet, like in the illustrations of The Little Prince of Antoine de Saint-Exupéry, and you throwing the ball from it. If the curvature of the ball throw is smaller then the curvature of the planet and the ball will land on the planet. If the curvature of the ball is bigger then the curvature of the planet it will “fall of” the planet, this is called the excape velocity. If you throw the ball in just the right way, that the curvature fits the planets our ball will just circle the planet (its in orbit). If the planet is bigger you need to throw faster, making the curvature of the thrown ball bigger. But there is a limit of how fast you can throw, that is the speed of light. There is no limit on how big mass (the planet) can get. If the “planet” is so big that the curvature of the ball thrown at fastest speed in any direction is still too small to “fall of” the “planet” than you have black hole. Because this also results in any “balls” thrown from a different planets (suns etc) not being able to bounce off our black hole, so all light (“balls”) “stays” on our imagainary blackhole-planet. If no balls (photons) can come or bounce off our big planet, we percieve it as black. (I know its not a precise explanation but its ELIF)
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