How does computer’s USB ports provide power for 48V phantom power?

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How do they provide enough power for 48V phantom power on audio interfaces? I don’t know much about electricity but it the number seems quite a lot?

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3 Answers

Anonymous 0 Comments

I’m not familiar with this device but it must not require all that much amperage. You can transform the 5v in 48v but the total amperage it can supply is still limited. Yould probably be lucky to get more than an amp or two out of a computer usb port

Anonymous 0 Comments

Power is the product of voltage and current. If you draw a low current at a high voltage the power is still lower.

USB has a 5V output at max 900mA so 4.5W power fot the USB 3.1 standard without power delivery addition. You can change the voltage with electonis but a increase voltage result in a decreased max current in the ideal case the power has not changed, in practice there is some loses in the conversion.

4.5/48 = 0.093A so if you use a standard USB port with ideal voltage conversion at 48V the map current that can be drawn is 0,093A = 93mA In practice components are not ideal so the max current is lower. But even as bad as 50% efficiency is 45mA

A quick look at what current is drawn results in https://www.sounddevices.com/phantom-powering-basics/ and toe the one there at 48V the current was between 0.8 and 10 mA. That will be no problem in delivering from a USB outlet

Anonymous 0 Comments

Phantom power is usually in the range of 4-22 milliamps, while a USB 2.0 port can output 500 mA.