How exactly could you measure the distance from the Earth to the Moon by triangulation? How is it done?

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I’m reading Bill Bryson’s book and came across this concept. Still can’t get my head around it. Would appreciate a proper explanation. Thanks.

In: Physics

2 Answers

Anonymous 0 Comments

I dont know that book, but it should not be all that complicated, as long as you have two observers on different parts of the earth.

Lets say, an astronomer in London watches the night sky and writes in his notebook “On April 17th, the moon passed just 0.1 degrees over the start Alpha Centauri”.

On the same day, an astronomer in Cape Town notes the same thing, only he sees the moon and the star 0.8 degrees apart.

Sometime later those two men meet and compare notes.

They now draw a small circle representing earth, and mark London and Cape Town at their appropiate places on that circle. They also draw a straight line from the earth to Alpha Centauri.

Now, all they have to figure out is where exactly on (or near) this line they have to place the moon so that there is a 0.7 degree angle between the lines moon-London and moon-Cape Town. Once they got that, they have a true-to-scale map of the earth-moon system in front of them.

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