If someone pulls an object once with long rope and another time with short rope on smooth surface and if work and displacement be same, explain which one the guy applied more force? (Do not consider friction.)

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I was reading my book because I have test tomorrow and I saw this question. Can anyone explain and answer this?

If someone pulls an object once with long rope and another time with short rope and if Work and Displacement be same, explain which one the guy applied more force? (Do not consider friction.)

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14 Answers

Anonymous 0 Comments

Is this question maybe relating to the internal stresses of a rope? Due to how ropes are woven, some of the force you apply is transferred into compressing/lengthening the rope. Longer rope means more material to deform before enough force is applied to move the object. The rope is also heavier and you gotta move that too.

Anonymous 0 Comments

Is this question maybe relating to the internal stresses of a rope? Due to how ropes are woven, some of the force you apply is transferred into compressing/lengthening the rope. Longer rope means more material to deform before enough force is applied to move the object. The rope is also heavier and you gotta move that too.

Anonymous 0 Comments

>if work and displacement be same, explain which one the guy applied more force?

This line is all you need

Work = Force * Displacement

If Work and Displacement are the same in both cases then Force *must* be identical

For a practical situation with a non-zero mass rope with some slight stretch to it the longer rope will require more work to be done because some energy is lost into the rope but since you’re ignoring friction you can also ignore non-ideal ropes and are just left with W=FxD

Anonymous 0 Comments

>if work and displacement be same, explain which one the guy applied more force?

This line is all you need

Work = Force * Displacement

If Work and Displacement are the same in both cases then Force *must* be identical

For a practical situation with a non-zero mass rope with some slight stretch to it the longer rope will require more work to be done because some energy is lost into the rope but since you’re ignoring friction you can also ignore non-ideal ropes and are just left with W=FxD