If there are two boxes. The first has a 100$ bill and a 1$ bill, and the second has two 100$ bills. If I puck a random box and take out a 100$ bill, whaat is the chance of me taking out another 100$ bill?

Question

I’m honestly stuck. I’ve seen people say 1/2, others 2/3. Something Monty Hall Problem, Bayes Theorem but I’m still confused so here I am.

Edit: I believe you are not allowed to change your box choice on the 2nd “turn” as that would make having two boxes pointless, wouldn’t it?

In: 10

Answer 1

I think that if you can’t change boxes, the probability doesn’t change depending on the box you choose first.
First pick, you have 3/4 chance of getting a $100 and 1/4 chance of $1.
If you picked a 100$ on the first pick, 2 of the remaining bill are 100$ and 1 is a 1$. So there’s a 2/3 probability you’ll pick a 100$