If you roll 6 times, what are the odds of getting a given number? It can’t be 100%, since there’s a good chance you won’t get the number on any roll, so what percent is it?
Edit: A lot of you are misinterpreting the question. I am asking what the combined odds are to get a given number at least once, not just the 6th roll.
In: Mathematics
66.5%.
To find the answer, you multiply out the odds of **NOT** getting a desired result. So, for each roll you have 5/6 chance of **NOT** getting the result you want, and you multiply that out by the number of rolls.
5/6 * 5/6 * 5/6 * 5/6 * 5/6 * 5/6 = 33.5%, which you then subtract from 100% to get 66.5%.
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