The way I understand it, you win on a 2 or 3; lose on a 7 or 11; push on a 12; go to point phase for 4-6 8-10. So that means you can win on 2 numbers, lose on 2, push on 1, and go to 50:50 odds with the others. Seems like the house doesn’t have an advantage. (As opposed to the Pass, where you lose on 3 and win on 2 in the come out.)
In: Mathematics
> So that means you can win on 2 numbers, lose on 2, push on 1, and go to 50:50 odds with the others.
Not exactly. You win on three rolls (1:1, 1:2, 2:1), lose on eight rolls (1:6, 2:5, 3:4, 4:3, 5:2, 6:1, 5:6, 6:5), and push on one (6:6). You are over twice as likely to lose than win.
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