The way I understand it, you win on a 2 or 3; lose on a 7 or 11; push on a 12; go to point phase for 4-6 8-10. So that means you can win on 2 numbers, lose on 2, push on 1, and go to 50:50 odds with the others. Seems like the house doesn’t have an advantage. (As opposed to the Pass, where you lose on 3 and win on 2 in the come out.)
In: Mathematics
7 is the most common combination of 2 dice. There are 11 possible outcomes from a roll of 2 dice (2 through 12.) But there’s only one way to make 2 – by rolling a 1 on each die. There’s also only one way to make 12 – by rolling a 6 on each die.
There are 36 possible combinations and only 11 outcomes. There are 6 possible ways to make 7, which means it’s 6 times as likely to roll a 7 as it is to roll a 2.
If you look at your outcomes listed above…
You win on a 2, which is 1/36, or on a 3, which is 2/36. You lose on a 7 or 11 – 6/36 or 3/36. You go to points on all other rolls. At the outset, you have a 3/36 chance of winning, a 9/36 chance of losing, and a 24/36 chance of moving on to the point phase.
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