Monty Hall question, but varied. I haven’t seen the option that no matter what you have a 40% chance overall to win. You always pick 1 of 3 doors, then 1 is discarded & you pick 1 of 2. So don’t you always have a 2/5 chance of being right no matter what?
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It’s 1/3 if you don’t switch, 2/3 if you do. It’s not intuitive but very easy to verify if you just work out the 3 possibilities in your head. If the correct door is B…
A: guess wrong door, switch to correct door.
B: guess right door, switch to wrong door.
C: guess wrong door, switch to correct door.
The key is you’ll never guess the wrong door and then switch to the other wrong door.
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