Monty Hall question, but varied. I haven’t seen the option that no matter what you have a 40% chance overall to win. You always pick 1 of 3 doors, then 1 is discarded & you pick 1 of 2. So don’t you always have a 2/5 chance of being right no matter what?
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Because there aren’t five doors, there are three. You choose one out of three doors, which makes you 2/3 likely to be wrong. This doesn’t change when one door is opened, so when you get to choose between your door and the remaining door, the chance you chose wrong remains at 2/3.
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