Monty Hall question, but varied. I haven’t seen the option that no matter what you have a 40% chance overall to win. You always pick 1 of 3 doors, then 1 is discarded & you pick 1 of 2. So don’t you always have a 2/5 chance of being right no matter what?
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The percentages don’t multiply like that.
If you make a random 1/3 guess you have a 33% chance.
If you make a random 1/2 guess you have a 50% chance.
The Monty Hall problem just creates the illusion that “keeping” your first choice gives you the 50/50 chance when you really only had the 1/3.
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