Probability of past instance

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In a hypothetical scenario,

if Lebron James made 10 successful shots in the same spot consecutively, what is the probability that his 11 shot is successful? Is it the same probability as the 1st? or did any of his prior shots affect his 11th throw?

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What about in the instance of coin toss, similar scenario,

if i throw head for 10 times, what is the probability that i will get another head in the 11th time?

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Thanks

In: Mathematics

10 Answers

Anonymous 0 Comments

Coin tosses are independent; flipping 10 heads in a row doesn’t affect the outcome of the

If you’re falling into the trap “11 heads is very unlikely, so the 10th flip is probably a tail” then notice that tye combination of flips HHHHHHHHHHH (11 heads) and HHHHHHHHHHT (11 heads followed by 1 tail) have the same probability of occurring; that is 0.5^11. They are both unique outcomes out of 2^11 total Possible outcomes

But it might be different for Lebron shooting freethrows. I don’t know anything about basketball, but maybe after 10 throws he is getting tired or careless and so is less likely to Make his 11th throw than his 1st.

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