Addition of velocities doesn’t work like that near the speed of light
In a classical reference frame, u=v+u’
In a relativistic reference frame, u=(v+u’)/(1+vu’/c^(2))
They just see the other rocket go by at very close to the speed of light, much closer than they actually are from a static reference frame.
Let’s say v=.9c and u’=.9c
u=1.8c/(1+.81c^(2)/c^(2)) = .99c (approximately)
And this is what you would see if you were on one rocket observing the other
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