The Monty Hall Problem I just dont get it.

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Why does the probability “lock in” and not change if you remove a variable but doubles for the other one?

I read it multiple times and it still doesnt make any logical sense to me.

In: Mathematics

33 Answers

Anonymous 0 Comments

There are three doors. If you picked the correct door (1/3 chance) then switching bones you. If you picked the wrong door (2/3 chance) then switching gets you the car. Since switching wins if you picked _either_ of the wrong doors, but staying only wins if you picked the _only_ correct door, switching has better odds (2/3).

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