The Monty Hall Problem I just dont get it.

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Why does the probability “lock in” and not change if you remove a variable but doubles for the other one?

I read it multiple times and it still doesnt make any logical sense to me.

In: Mathematics

33 Answers

Anonymous 0 Comments

You need to think about it in terms of the chance you were wrong.

When you pick one of three doors, there’s a 2/3 chance you chose a door without the prize behind it.

The game master then opens one of the doors you didn’t choose, to show you there wasn’t a prize behind it. But this doesn’t tell you anything you didn’t already know – you knew there was only one door with a prize, so at least one of the two you didn’t choose would have to also not have a prize. Your chance of having picked the wrong door is still 2/3, so you should switch, turning that into a 2/3 chance of winning.

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