The Monty Hall Problem I just dont get it.

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Why does the probability “lock in” and not change if you remove a variable but doubles for the other one?

I read it multiple times and it still doesnt make any logical sense to me.

In: Mathematics

33 Answers

Anonymous 0 Comments

You have a one in three chance to be correct with your guess.

The prize has a two in three chance of being behind one of the two doors you didn’t pick.

The host does not open one of these doors randomly, he only opens one there is no prize behind.

Therefore the door he invites you to switch to has a two in three chance of having the prize.

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