The Monty Hall Problem I just dont get it.

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Why does the probability “lock in” and not change if you remove a variable but doubles for the other one?

I read it multiple times and it still doesnt make any logical sense to me.

In: Mathematics

33 Answers

Anonymous 0 Comments

If you picked wrong door, the host tells you outright which of the other 2 is the right one.

If you picked right door, he opens a random one and provides no extra information.

2/3 of times, you’ve picked wrong one to begin with, so the first scenario applies.

Some people find it easier to grasp if you imagine 100 doors instead of 3, with the host always opening all but 1 (+ the one you chose)

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