The Monty Hall Problem I just dont get it.

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Why does the probability “lock in” and not change if you remove a variable but doubles for the other one?

I read it multiple times and it still doesnt make any logical sense to me.

In: Mathematics

33 Answers

Anonymous 0 Comments

The probability would only change if the doors were shuffled each round.

The classic explanation changes the scenario from 3 doors to 100. If you pick 1 door, then I open 98 wrong doors, would you stay with your initial 1/100 pick or switch to the only other remaining closed door?

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