Let’s ignore the airliner crashes and simplify by going to coins (1 in 2).
If two people use the same coin, they both have a 1/2 chance of H. If they use two coins, 1/4 both H, 1/4 both T, and 1/2 one H, one T.
Each person still have the same probability of H in all cases. The probability of *both* getting H is smaller.
Your question isn’t clear so there’s not really a good way to answer.
Try these: https://www.mathsisfun.com/data/probability-events-conditional.html https://youtu.be/ibINrxJLvlM
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