If you bet $100, your odds of winning are around 50% and if you lose, bet $200, and so on and so forth until you win, and then cash out with a guaranteed profit. Assuming odds of black are 47.37% as per American roulette, your odds of not winning a single one after 6 tries are 0.02125 (I think) and decrease exponentially after each subsequent try.
In: 93
Also, think about it – the odds of getting 10 reds in a row is small but not zero. Say there’s a 1/1000 chance of getting all reds, so you make your bet on black as you’ve said. Every time you lose you have to bet double just to win your initial target back, and each bet is independent so all you need to do is lose 4/5 in a row and you will be betting 10x your initial bet, but the win is still the same. Do you get me? Bet 10, lose, bet 20, lose, bet 40, lose, bet 80, lose, now all of a sudden you are making £160 bet, at 50/50 odds, and all you can win is your money back plus £10.
That bet doesn’t care that you’ve just lost 5 in a row, it’s still a 50/50 bet. Only now you have 50% chance of being up £10, and a 50% chance of being down £310. Ergo, a bad bet. Don’t do it
Latest Answers