Anything multiplied by 0 is 0 right so why does x number raised to the power of 0 = 1? isnt it x^0 = x*0 (im turning grade 10 and i asked my teacher about this he told me its because its just what he was taught 💀)
In: Mathematics
Ok so
x^0 = x^(n-n), since n-n is of course = 0
Know, for properties of however those are called in English, I think exponentials, x^a / x^b = x^(a-b)
So you can now imagine how
x^0 = x^(n-n) = x^n / x^n =
Since a number divided by himself is 1
x^0 = x^(n-n) = x^n / x^n = 1
EDIT:
You can now interrogate yourself on how
x^a / x^b = x^(a-b)
Since x^a means you will multiply x for it self a times, you will get a thing like
x^4 / x^3 = (x x x x) / (x x x) = x = x^1 = x^(4-3)
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