# Why does flipping the second fraction around and then multiplying work when dividing two fractions?

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Eg. 8 over 3 divided by 1 over 3 = 8 over 3 times 3 over 1

In: 13 Ok, let’s simplify this a bit.

When you take any number and divide it by 1/3, let’s say you’re dividing 5 (instead of 8 over 3, it works the same, 5 is just a simpler example.)

So you have 5 divided by 1/3.

This is like taking 5 apples, and dividing them into groups where each group only has 1/3rd of an apple.

Which is like cutting an apple into thirds.

Which is like taking 1 Apple and making it 3 pieces. One piece for each group.

So for each apple, you get 3 pieces, so if you divide all 5 apples, you get 15 pieces. 5 divided by 1/3 is 15.

Just like multiplying 5 by 3.

Multiplication and division are just opposite functions.

For example, you could do this in reverse. Say you want to take 10, and divide it by 2. That gives you 5. Or you could take 10, and multiply it by 1/2 (or 0.5). Which also gives you 5. Division is the opposite of multiplication.

So dividing by a dividing thing is a double-division, so the opposite of the opposite of multiplication; which is just multiplication.

Because division and multiplication are the same kind of thing(ish), we can always do them in any order. So:

> 8/3 divided by 1/3

can be split up into:

> 8 divide by 3, divide by 1, divide by “divide by 3”

but that “divide by divide by 3” is a double division, so a multiplication:

> 8 divide by 3, divide by 1, multiply by 3

We can now re-order that:

> 8 divide by 3, multiply by 3, divide by 1

and then join these bits up together again to get:

> 8/3 multiply by 3/1

It is a deceptively complicated process but it only relies on division being the opposite of multiplication, and that you can re-order (and regroup) division and multiplication.

And understanding that fractions are the same as division.

[This also means that phrasing and brackets are important. 8/1/3 could be “8 divide by 1, divide by 3”, or it could be “8 divide by (1 divided by 3)” (so 8 multiplied by 3). ] Say that you have

> (a/b) / (c/d) = e

You can multiply both sides by (c/d):
> ((a/b) * (c/d)) / (c/d) = e * (c/d)

You can then simplify the left side since (c/d) / (c/d) = 1
> (a/b) = e * (c/d)

You can now multiply both sides by d, and then divide by c. c cannot be 0, or you would have a division by 0 to begin with.
> (a/b) * d = e * (c/d) * d = e * c

> (a/b) * (d/c) = e * (c/c) = e

And both (a/b) / (c/d) and (a/b) * (d/c) equal e, which means they are equal. Division does not exist. There is only Multiplication and the Multiplication of Reciprocals. This is why you cannot divide by Zero, Zero has no Reciprocal khalamar’s answer is correct and probably the simplest one so far.
But we can do even simpler, in the same spirit.