I have read through around 10 articles and webpages on this problem, and still don’t understand. I’ve run simulations and yes, switching does get you better odds, but why?
In: Mathematics
Here’s a fresh point of view that usually doesn’t get mentioned.
Let’s change the rules slightly. After the host opens one of the doors, you can either keep the one door or switch to the two other doors. So you can choose two doors instead of one. Choosing an open losing door is meaningless, so these rules are equivalent to the original ones.
Let’s make another small change; the host doesn’t open a door. Even if the host doesn’t open a door, you already know that one of the other two doors is a losing door. The host opening the losing door doesn’t change anything, so these rules are equivalent to the original ones.
The Monty Hall problem is just a confusing way to ask whether you want to open one or two doors.
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