Why is the taylor series for ln(x+1) so similar to the tailor series sin(x) or cos(x), yet the functions themselves are not at all?

292 views

Why is the taylor series for ln(x+1) so similar to the tailor series sin(x) or cos(x), yet the functions themselves are not at all?

In: 0

6 Answers

Anonymous 0 Comments

I’m a bit confused, they aren’t the same at all. The taylor series terms for ln(x+1) are x^n / n alternating signs.

The taylor series for sin(x) has terms x^2n+1 / (2n+1)! (alternating signs).

The taylor series for sin(x) has terms x^2n / (2n)! (alternating signs).

These are very different.

You are viewing 1 out of 6 answers, click here to view all answers.