why is x to the power of 0 always 1?

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I tried to google a proof, and i found that it comes from the formula: x^1*(1/x^1) where the two x^1s cancel eachother out. I wasn’t satisfied with the answer, so i am still somewhat confused.

Usually when there’s some math i don’t get, i try to imagine a scenario irl, where a formula would apply. This always helps, but i can’t find one here.

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9 Answers

Anonymous 0 Comments

To make it make sense when we transition to negative exponents.

3^3 = 3•3•3 = 27

3^2 = 3•3 = 9 (27/3)

3^1 = 3 = 3 (9/3)

3^0 = 1 (3/3)

3^-1 = 1/3

3^-2 = 1/9 ((1/3)/ 3)

3^-3 = 1/27 ((1/9)/3)

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