X² is X times X.
X¹ is X.
In X^Y Y is the factor that decides how many Xs are getting multiplied.
So why is X⁰ 1? It comes out of nowhere. Zero Xs are getting multiplied, so there’s no numbers being multiplied, meaning there’s nothing.
In: Mathematics
So think of it this way:
X^4 / X^2 is just (XXXX)/(XX) = X^2
X^3 / X^2 is just (XXX)/(XX) = X
X^2 / X^2 is just (XX)/(XX) = 1
In each of these, X^a / X^b = X^(a-b)
If a = b, then we have X^0
This just means we have the same number of X’s in the numerator and denominator, so it’s just some number divided by itself
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