Eli5: Using Boyle’s law to calculate volume in an oxygen tank

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I’m hoping someone can help me understand this concept.

So according to Boyle’s Law, pressure and volume are indirectly proportional
P1V1=P2V2

With that in mind when pressure goes up, volume goes down. Why does the opposite happen when you are decreasing pressure in an Oxygen tank?

I’m thinking it has to do with the release of the gas but is there a different formula that calculates the remaining volume when you are decreasing the PSI on the gauge?

Or am I using the equation incorrectly.

In: Physics

4 Answers

Anonymous 0 Comments

Not sure I understand your question, but…

In a cylinder, the volume is fixed (i.e. the cylinder isn’t getting any larger/smaller); however the volume that the gas takes up changes under pressure.

Avagadro’s constant – 1 mole of gas takes up 22.4dm3 of volume at standard temperature & pressure. If you take 1 mole of gas and change increase the pressure, then it will take up less space.

Imagine the volume of your cylinder is 22.4L. Fill it with an uncompressed gas, and you’ll end up with 1 mole of it; compress it and you have more gas in there.

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