Not sure if I understand what the question is.
Regardless, I hope the following will give some insight:
If you pick 2 numbers, X and Y, at random, X and Y can either be even, or odd. So, we have the following 4 possibilities. (Not 3)
– X, Y are both even -> sum is even
– X is even, Y is odd -> sum is odd
– X is odd, Y is even -> sum is odd
– X, Y are both odd -> sum is even
I think now it’s easy so see that the odds are 1/2 and 1/2.
Edit: formatting
Latest Answers