How does Hawking Radiation work?

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[Hawking Radiation](https://en.wikipedia.org/wiki/Hawking_radiation) is a is radiation that is predicted to be produced by black holes. Anti-particle- and particle-pairs spontaneously appear close to the event horizon of the black hole. If the anti-particle falls into the black hole, while the corresponding particle can escape, a particle inside the black hole will be annihilated an “radiated away” by the escaping particle.

My question is: why is it only the anti-particle that falls into the black hole? Shouldn’t the particle have an equal probability of falling into the black hole, keeping the whole system at an equilibrium?

In: Physics

3 Answers

Anonymous 0 Comments

It is dependent on the current net charge of the black hole. The opposite charge will fall in, the like charge will repel, whichever it may be

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