In practice, yes, because the ball is going to induce motions in the water. That prevents a boundary layer (“thin shell around a thing”) of cooler water from surrounding the ball, making the heat transfer from the bowl of water more efficient. But how much it does so depends on properties of the water (e.g. viscosity) and of the ball (how smooth is its surface?) – an idealized frictionless ball wouldn’t create any current and thus wouldn’t affect heat transfer.
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