You can… in the trivial ring.
In other division rings, unfortunately, it’s not possible, because there is no multiplication inverse of 0. I’ll mark the multiplication inverse of a number n as n^(T)
0 0^(T) = 1 (definition of multiplication inverse)
0 = 1 (definition of 0)
That statement is only compatible with a trivial ring. To show that, we pick any element of a ring R. Then
0r = 1r (multiplying both sides with r)
0 = r (definition of 0 and 1)
This shows that all elements of that ring are equal to zero. This means that the ring is just {0}
There is a way to work around that, by working with a wheel instead of a division ring, Wheel is similar to a ring, but with a slightly different axiom: [https://en.wikipedia.org/wiki/Wheel_theory](https://en.wikipedia.org/wiki/Wheel_theory)
A common way to obtain a wheel is by adjoining a bottom element to a projective line. The bottom would be the solution of 0/0
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