Seems weird any way I think about it. Thanks!
In: Mathematics
Different roles of different or the same die have no connection with each other.
Each new roll has the same chance of outcome as the last. There is no memory involved.
Rolling a 6 two times in a row does not make the next roll anymore or less likely to be a 6.
If you roll a die twice (or two dies once) the possible outcome average out to 7 and make 7 the most likely sum you will get.
If you roll a die once, all six different outcomes are equally likely and they will average out to 3.5.
If you roll two die you will have 36 potential outcomes.
1st die | 2nd die | Sum
—|—|—-
⚀ | ⚀ | 2
⚀| ⚁ | 3
⚀|⚂| 4
⚀|⚃ |5
⚀|⚄ |6
⚀| ⚅|7
⚁| ⚀ | 3
⚁| ⚁ | 4
⚁ |⚂ | 5
⚁ |⚃ |6
⚁ |⚄ |7
⚁ |⚅ |8
⚂| ⚀ | 4
⚂| ⚁ | 5
⚂|⚂ | 6
⚂|⚃ |7
⚂|⚄ |8
⚂| ⚅ |9
⚃ |⚀ | 5
⚃ |⚁ | 6
⚃ |⚂ | 7
⚃ |⚃ |8
⚃ |⚄ |9
⚃ |⚀ |6
⚄ |⚁ | 7
⚄ | ⚂| 8
⚄ |⚃ |9
⚄ |⚄ | 10
⚄ |⚅ | 11
⚅|⚀ | 7
⚅|⚁ | 8
⚅|⚂ | 9
⚅|⚃ | 10
⚅|⚄ | 11
⚅|⚅| 12
As you can see, you have 6 out of 36 chances of having sum of 7, 5 out of 36 chance for having a sum 8 or 6 each, 4 chances each of having 9 and 5 and so on and just one chance for having a 2 or 12.
So 7 is not just the result that everything else averages out to it is also the result that you are most likely to get.
Once you have thrown a die and wait for the result of the 2nd die you can throw 30 of the 36 entries in the table above away. you will still have a 1 in 6 chance of both dies adding up to 7 but there will be 5 other equally likely results that are not 7.
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