If I throw something upwards will the gravity slow it down faster?

174 views

So idk if this makes sense so I’m going to use numbers. If I take something, and shoot it let’s say a bullet. Into the air. The first second it will be slowing down at 9.81m/s if I’m not mistaking because gravity is pulling it down that fast. At the 2nd second. Will gravity be pulling it down at 9.81m/s still or will it go to 19.62m/s? Like will the speed be stacking essentially for how fast it slows down?

In: 8

7 Answers

Anonymous 0 Comments

The acceleration towards the center of mass (down) will remain constant. Its the velocity that will increase over time as the object is unsupported.

So it will always be accelerating at 9.8 m/s^2.

So if you throw the object up at 9.81 m/s (assuming zero air resistance) after 1 second the object will be stationary in the air. It will then accelerate at the same rate downward, reaching the same height you threw it from after one more second (2 seconds total). Shortly after it will hit the ground at your feet. If you are on a cliff it will continue falling. After 2 seconds of falling it will be moving at 19.62 m/s. But it will still only be accelerating at 9.81 m/s^2.

Edit to add: You are confusing velocity and acceleration. Velocity is how fast something is changing position over time. Acceleration is how much it is changing velocity over time.

You are viewing 1 out of 7 answers, click here to view all answers.
0 views

So idk if this makes sense so I’m going to use numbers. If I take something, and shoot it let’s say a bullet. Into the air. The first second it will be slowing down at 9.81m/s if I’m not mistaking because gravity is pulling it down that fast. At the 2nd second. Will gravity be pulling it down at 9.81m/s still or will it go to 19.62m/s? Like will the speed be stacking essentially for how fast it slows down?

In: 8

7 Answers

Anonymous 0 Comments

The acceleration towards the center of mass (down) will remain constant. Its the velocity that will increase over time as the object is unsupported.

So it will always be accelerating at 9.8 m/s^2.

So if you throw the object up at 9.81 m/s (assuming zero air resistance) after 1 second the object will be stationary in the air. It will then accelerate at the same rate downward, reaching the same height you threw it from after one more second (2 seconds total). Shortly after it will hit the ground at your feet. If you are on a cliff it will continue falling. After 2 seconds of falling it will be moving at 19.62 m/s. But it will still only be accelerating at 9.81 m/s^2.

Edit to add: You are confusing velocity and acceleration. Velocity is how fast something is changing position over time. Acceleration is how much it is changing velocity over time.

You are viewing 1 out of 7 answers, click here to view all answers.