Raffle ticket odds, does buying say 10 out of 28,000, give you 1/2800 chance on every ticket or 1/28000?
In: Mathematics
Maybe this will help people get what u/berael and u/Medved are saying.
Obviously, if we have zero tickets in a lottery/raffle we have zero chance of winning.
After buying the first ticket the increase in the chance of winning is increased 100% because we started with zero and now have some chance.
What is the percent increase in the chance of winning when we buy the second ticket?
It’s so low as to be almost zero.
The same applies for subsequent tickets.
Each ticket increases the chance of winning mathematically but in a practical sense almost not at all.
I stayed away from the actual numbers to keep it simple (and because I just woke up from a nap) but I’m sure some big-brain out there will run the numbers for us.
Here’s another way to look at it.
The chance of winning a 6/49-type lottery is 1 in 13,983,816.
Source: [Wikipedia Lottery Mathematics]( https://en.wikipedia.org/wiki/Lottery_mathematics#%3A%7E%3Atext%3D7_External_links-%2CChoosing_6_from_49%2Chappening_is_1_in_13%2C983%2C816.?wprov=sfla1)
That’s approximately the same as the odds of being struck by lightning – twice – in the same place.
Using OP’s example of having a 1-in-10 chance means buying 10% of the tickets.
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