The Monty Hall math problem

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I was watching Brooklyn 99 Season 4 Episode 8 around the 5 minute mark

The problem goes “There are 3 doors behind one of which is a car. You pick a door and the host, who knows where the car is, opens a different door showing nothing behind it. He asks if you want to change your answer.

Apparently the math dictates that you have better chances if you change your decision. Why? 2 doors 50/50 chance, no?

One character (Kevin) says it’s 2/3 if you switch 1/3 if you don’t. What? How? Please help.

In: Mathematics

27 Answers

Anonymous 0 Comments

The explanation that made this click for me was to imagine 100 doors. Your chance of being right is 1%, and that leaves a 99% chance that you guessed wrong. The host opens 98 doors but this does not change the chance of your initial guess being wrong.

Pretty sure the experts would say this is a weird way to think about it but the visual is pretty convincing 👍

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