Why in E=mv^2 the kinetic energy increases to the square of the velocity???

Question

I wonder if there is an intuitive explanation for this

edit: It’s E= 1/2 m v^2 actually

In: 0

Answer 1

Energy is a force applied over a certain distance, or F*d

So if E = F*d and F = m*a, then E = m*a*d.

But a*d is just v^(2) (acceleration is distance over time^(2) so multiplying that by distance gives you distance^(2)/time^(2) or (distance/time)^(2) and distance/time is velocity)