Why does multiplying or dividing two negative numbers produce a positive?

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Why does multiplying or dividing two negative numbers produce a positive?

In: Mathematics

7 Answers

Anonymous 0 Comments

The Khan Academy and others explain it using distributive property of maths, which is therefore a pre-requisite. We did this at age 11 in UK. I’ll show it quickly here:

What is -5 x (3 – 3) ? Ans. 0, since 3 – 3 is 0 and anything multiplied by 0 is 0.
Using distributive property of multiplication: -5 x (3 – 3) = -15 + (-5 x -3) = 0
So it must be true that -5 x -3 = +15.

The other intuition is looking at a pattern such as:

3 x -5 = -15
2 x -5 = -10
1 x -5 = -5
0 x -5 = 0
-1 x -5 = +5
-2 x -5 = +10

And hopefully feel that this makes sense, everything is consistent.

(Ughh, not formatting as it appears on iPad sorry)

Anonymous 0 Comments

One way to understand this is to treat real numbers as ‘phasors’.

A phasor is simply a magnitude and an angle. When you multiply two phasors, you multiply the magnitudes and you add the angles.

So instead of thinking 2 * -2 = -4, instead think of 2 (angle of 0) * 2 (angle of 180 degrees) = 4 (angle of 180 degrees).

A good way to visualize this is to think of a 2d grid rather than a number line. When you multiply numbers, you move your starting point further/closer to the origin while rotating that point around the origin.

With this mental model, it should become clear that multiplying 2 (angle of 180) by 2 (angle of 180) must yield 4 (angle of 0) – you’re just multiplying two positive numbers for the magnitude and adding the angles.

Now, this may seem a bit weird. But it should be obvious that everything you could possibly do with standard real numbers can also be done with phasors – you just represent positive reals with an angle of 0 and negative numbers with an angle of 180. Indeed, phasors are a ‘superset’ of reals – they include every possible real and we can express every possible algebraic combination of reals with them.

As a result, any time you could use reals, you can use phasors instead – and if our multiplication with phasors yields the result you’re pondering, then our multiplication with reals must as well.

Anonymous 0 Comments

My teacher used to say “use the word ‘of’ instead of ‘times’ when you’re multiplying. So 2 of 2 = 4. When it comes to multiplying negatives, think of it like a “opposite negative.”

So, if we have 2 of -2, I’m doubling the amount of deficit. If we have -2 of -2 it’s like reversing amount of deficit since it’s the opposite.

Anonymous 0 Comments

If you are comfortable with multiplying out (a – b)^2 you will find that the -b^2 term i.e. -b x -b MUST be positive.
e.g. suppose a=10 b=3 then result of above expression must be 7^2 = 49. Knowing this, when we expand the terms, a^2 = 100, -2ab = -60 so -b x -b = -b^2 = +9 to give 49 when the terms are summed.
HTH.

Anonymous 0 Comments

I owe you $10. You can interpret that as me having -$10.

I mow your lawn and you cancel my debt. That’s like subtracting that -$10, which is the same as adding $10.

I owe 5 people $10. That like having 5 x -$10 = -$50.

I mow all of their yards. I’m subtracting that debt five times, so -5 x -$10 = $50

Anonymous 0 Comments

Think of it as the number of times the numbers divide, -10/-5 = 2 because negative ten divides by negative five twice not negative twice.

Anonymous 0 Comments

Multiplying is easier to grasp.

Let’s go with a small problem. -2×2

Let’s label the negatives using dots. A ° is a negative.

So -2 = °°

If I have -2 two times that means I have °° °°

So count how many negative dots we have. We have °°°°. Which is 4 negative counters. Or -4.